Discussion
The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
Answer: A
\[ l = 3b \quad\Longrightarrow\quad 2(3b + b) = 96 \quad\Longrightarrow\quad 8b = 96 \]
\[ b = 12 \text{ m}, \qquad l = 36 \text{ m} \]
\[ A = 36 \times 12 = 432 \text{ m}^{2} \]
The perimeter contains four "breadths" worth of length in total (\( 2 \times 3b + 2 \times b \)), which is what makes the division by 8 so clean.
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