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A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?

  • A.Rs.3600
  • B.Rs.3700
  • C.Rs.3800
  • D.Rs.3900

Answer: D

The two roads cross, so their shared square must not be counted twice.

\[ \text{road along the length} = 80 \times 10 = 800 \text{ m}^{2} \]

\[ \text{road along the breadth} = 60 \times 10 = 600 \text{ m}^{2} \]

\[ \text{overlap} = 10 \times 10 = 100 \text{ m}^{2} \]

\[ \text{total} = 800 + 600 - 100 = 1300 \text{ m}^{2} \]

\[ \text{cost} = 1300 \times 3 = \text{Rs. } 3900 \]

Forgetting to subtract the crossing gives Rs. 4200 - the intersection belongs to both roads but is paved only once.

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