Discussion
The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
Answer: A
Let the base be \( b \); the altitude is then \( 2b \).
\[ A = b \times 2b = 2b^{2} = 128 \]
\[ b^{2} = 64 \quad\Longrightarrow\quad b = 8 \text{ m} \]
A parallelogram's area is base times perpendicular height, with no factor of one half - that half belongs to the triangle.
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