Discussion
Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
Answer: B
A diagonal splits the quadrilateral into two triangles that share it as their base, with the offsets as their heights.
\[ A = \frac{1}{2} d (h_{1} + h_{2}) \]
\[ = \frac{1}{2} \times 20 \times (9 + 6) = 10 \times 15 = 150 \text{ cm}^{2} \]
The offsets are the perpendiculars dropped onto the diagonal from the two opposite corners, which is why they add before the halving.
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