Discussion
If \(x/y = 6/5\), the value of \(\frac{x^2+y^2}{x^2-y^2}\) is:
Answer: B
Take \( x = 6k \) and \( y = 5k \).
\[ \frac{x^{2}+y^{2}}{x^{2}-y^{2}} = \frac{36k^{2}+25k^{2}}{36k^{2}-25k^{2}} \]
\[ = \frac{61}{11} \]
The \( k^{2} \) cancels, so only the ratio matters.
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