Discussion

A number is first increased by 20% and then decreased by 10%. Find the net percentage change.

Answer: C

We can use the successive percentage change formula: \(A + B + \frac{AB}{100}\).

Here, A = +20 (increase) and B = -10 (decrease).

Net change = \(20 + (-10) + \frac{20 \times (-10)}{100}\)

= \(10 - \frac{200}{100} = 10 - 2 = 8\)%.

Since the result is positive, it is an 8% increase.

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