Discussion
A number consists of two digits. If the digits interchange places and the new number is added to the original number, the resulting number will always be divisible by:
Answer: B
Let the two-digit number be 10x + y, where x is the ten's digit and y is the unit's digit.
The reversed number is 10y + x.
Their sum is \((10x + y) + (10y + x) = 11x + 11y\).
Sum = 11(x + y).
Since the sum is a multiple of 11, it will always be divisible by 11.
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