Discussion

The sum of four consecutive odd numbers is 112. The smallest number is:

Answer: A

Four consecutive odd numbers are symmetric about their average.

\[ \frac{112}{4} = 28 \]

The four numbers straddle 28 in steps of 2:

\[ 25,\ 27,\ 29,\ 31 \]

So the smallest is 25. Setting up \( x + (x+2) + (x+4) + (x+6) = 112 \) gives \( 4x + 12 = 112 \) and the same answer.

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