Discussion

Find the total number of prime factors in the expression \(4^{11} \times 7^5 \times 11^2\).

Answer: A

First, express all bases as prime numbers.

\(4^{11} = (2^2)^{11} = 2^{22}\).

The expression is \(2^{22} \times 7^5 \times 11^2\).

The total number of prime factors is the sum of the exponents of the prime bases.

Total prime factors = 22 + 5 + 2 = 29.

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