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\( \frac{2}{3} + \frac{4}{5} \) is-

  • A.\( \frac{6}{8} \)
  • B.\( 1\frac{6}{15} \)
  • C.\( 1\frac{7}{15} \)
  • D.\( \frac{8}{15} \)

Answer: C

The sum is \( 1\frac{7}{15} \).

Use the common denominator 15:

\[ \begin{aligned} \frac{2}{3} + \frac{4}{5} &= \frac{10}{15} + \frac{12}{15} \\ &= \frac{22}{15} = 1\frac{7}{15} \end{aligned} \]

\( \frac{6}{8} \) is the common error of adding numerators and denominators separately. \( \frac{8}{15} \) multiplies the numerators over the common denominator, and \( 1\frac{6}{15} \) is one fifteenth short of the true sum.

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