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The sum of \( 1 - 1 + 1 - 1 + 1 - 1 \cdots \) to even number of terms is-

  • A.zero
  • B.−1
  • C.+1
  • D.2

Answer: A

The sum is zero.

Pair the terms: \( (1 - 1) + (1 - 1) + \cdots \). With an even number of terms every 1 is matched by a \( -1 \), so each pair is 0 and the total is 0.

With an odd number of terms one extra +1 is left over, giving 1; that is the trap in the +1 option. −1 and 2 cannot be reached by any number of terms.

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