Discussion
Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by :
Answer: B
D and E together equal B, C and F.
Everyone starts with 10. Following the transfers:
- F borrows 2 from A: A 8, F 12.
- F gives 5 to C: F 7, C 15.
- C gives 3 to B: C 12, B 13.
- B gives 6 to D: B 7, D 16.
- D passes 1 to E: D 15, E 11.
D + E = 26, and B + C + F = 7 + 12 + 7 = 26. A, B and C give 27, A, B and F 22, A, C and F 27.
The total number of cards stays 60 throughout, which is a quick check on the bookkeeping: 8 + 7 + 12 + 15 + 11 + 7 = 60.
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