Discussion
The total armature ampere-turns of a dc machine per pole are
Answer: A
Correct answer: \( I_aZ/2AP \) for \( Z \) conductors and \( A \) paths
Each of the \( Z \) conductors carries \( I_a/A \), and \( Z/2 \) turns are formed from them, spread over \( P \) poles: \[ \mathrm{AT\ per\ pole} = \frac{I_a Z}{2AP}. \] The result is proportional to the load current, which is why armature reaction grows with load and why the interpoles correcting it must carry that same current.
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