Discussion
A four-pole lap-wound machine with 400 conductors carrying 200 A has armature ampere-turns per pole of
Answer: A
Correct answer: 2,500
For a lap winding the number of paths equals the number of poles, so \( A = P = 4 \): \[ \frac{I_a Z}{2AP} = \frac{200 \times 400}{2 \times 4 \times 4} = \frac{80{,}000}{32} = 2500. \] A wave winding would have \( A = 2 \) regardless of the pole count, which doubles the figure - so the winding type must be established before the formula is applied.
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