Machine-translated by Google. Questions are authored in English.
Top

Discussion

Predict the major product of the following reaction :

2-Amino-3-methoxybenzoic acid treated with 1. HONO, 2. R-NH2

  • A.Benzene with OMe and NH-R on adjacent carbons (ortho)
  • B.Benzene with OMe and NHR in a 1,3 (meta) relationship
  • C.Benzene with NHR and OMe on opposite carbons (para)
  • D.Benzene with OMe in the middle flanked by two NHR groups on neighbouring carbons

Answer: B

The product is (B), with NHR meta to OMe.

Diazotisation of an anthranilic acid gives the benzenediazonium-2-carboxylate, which loses N2 and CO2 to form benzyne. Here the methoxy group ends up next to one end of the triple bond: 3-methoxybenzyne.

The amine adds to the benzyne carbon farther from OMe. That puts the developing aryl anion on the carbon next to OMe, where the electronegative oxygen stabilises it inductively; protonation then gives the 3-methoxy (meta) product. Addition to the near carbon would place the anion away from OMe and give the ortho product (A), the minor pathway. (C), the para product, cannot come from a 2,3-benzyne at all, and (D) would need two additions.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.