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In the following reaction sequence

4-(Methoxymethoxy)indane treated with (i) sec-BuLi, THF, (ii) ZnCl2 to give P; P with 3-bromopyridine and Pd(PPh3)4 in THF gives Q

the major products P and Q, respectively, are:

  • A.ZnCl and then 3-pyridyl at C6, meta to the OMOM group
  • B.ZnCl and then 3-pyridyl at C5, ortho to the OMOM group
  • C.ZnCl and then 3-pyridyl at C7, para to the OMOM group
  • D.ZnCl and then 3-pyridyl on the benzylic CH2 next to the OMOM side

Answer: B

The answer is (B): metalation, and then the pyridyl group, ortho to the OMOM group.

The methoxymethyl ether is a strong directing group for ortho-lithiation: its oxygens coordinate sec-BuLi and deliver it to the adjacent ring C-H. Of the two positions ortho to the OMOM group in 4-(methoxymethoxy)indane, one is the ring-fusion carbon, which has no hydrogen, so lithiation occurs at C5. ZnCl2 exchanges Li for ZnCl, giving the arylzinc P.

A Negishi coupling with 3-bromopyridine under Pd(PPh3)4 then joins the pyridin-3-yl group to C5 with retention of position, giving Q.

(A) and (C) metalate positions meta and para to the directing group, which sec-BuLi does not reach, and (D) deprotonates a benzylic CH2, which the directing group does not favour.

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