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The major product formed in the given reaction is

2-(Trimethylsilyl)phenyl triflate plus 1-phenylcyclohexene, with CsF in CH3CN at room temperature

  • A.Cyclohexene with a phenyl on the sp3 carbon next to the double bond and a second phenyl on the alkene carbon
  • B.Cyclohexene with a phenyl on an allylic sp3 carbon and a second phenyl on the far alkene carbon
  • C.Cyclohexene with a phenyl on each of the two carbons opposite the double bond (3,6-diphenylcyclohexene)
  • D.Cyclohexene with one phenyl on an sp3 carbon next to the double bond and a second phenyl on a further sp3 carbon

Answer: A

The major product is (A), the 1,6-diphenylcyclohexene.

Fluoride attacks the silicon of 2-(trimethylsilyl)phenyl triflate, and loss of triflate generates benzyne under mild conditions. Benzyne is a reactive enophile, and 1-phenylcyclohexene, with allylic hydrogens, undergoes an aryne ene reaction with it: an allylic hydrogen moves to one aryne carbon while the other aryne carbon bonds to the alkene, and the double bond shifts.

The hydrogen comes from C6, the allylic CH2 next to the phenyl-bearing C1, and the new aryl bond forms at C2, the unsubstituted alkene carbon, which is far less hindered than C1. The double bond moves to C1=C6. The new phenyl (from benzyne plus H) therefore sits on an sp3 carbon next to the vinylic carbon carrying the original phenyl, as in (A).

(B) keeps the double bond where it was and adds the aryl at the other allylic position, which is a substitution, not an ene product. (C) and (D) place the phenyls 1,4 or 1,3 apart, which an ene reaction of this alkene cannot produce.

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