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Discussion

Among the given options, the possible product(s) that can be obtained from the following reaction is/are

2-Methoxynaphthalene treated with CHCl3 and aqueous NaOH at 70 degrees C.

  • A.Chloro benzotropone: benzo-fused cycloheptatrienone with Cl next to the C=O
  • B.Hydroxy benzotropone: benzo-fused cycloheptatrienone with an OH on the ring
  • C.1-(Dichloromethyl)-2-methoxynaphthalene
  • D.3-Methoxy-2-naphthaldehyde

Answer: A

The product is (A), the chloro benzotropone.

Chloroform and aqueous NaOH generate dichlorocarbene. With 2-methoxynaphthalene there is no free OH, so no phenoxide forms and the Reimer-Tiemann route to an aldehyde is closed. Instead the carbene adds to the electron-rich C1=C2 bond to give a dichlorocyclopropane. This opens with loss of chloride to a ring-expanded benzocycloheptatrienyl (benzotropylium) cation, stabilised by the methoxy group, and hydrolysis of that oxocarbenium centre gives the ketone with chlorine on the neighbouring carbon.

(C) and (D) are Reimer-Tiemann-type products, which need a phenoxide to activate the ring and to hydrolyse CHCl2; (D) also places the CHO at C3. (B) would need the C-Cl carbon to become a C-OH, which the conditions do not bring about.

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