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The major product formed in the following reaction sequences is

N-Benzyl-2-iodoaniline plus ethyl (E)-4-bromobut-2-enoate, then (i) K2CO3, MeCN; (ii) Pd(PPh3)4, Et3N, DMF; (iii) H2, Pd/C, EtOH/AcOH.

  • A.Ethyl 1,2-dihydroquinoline-4-carboxylate
  • B.Ethyl indole-3-acetate
  • C.Ethyl 1,2,3,4-tetrahydroquinoline-4-carboxylate
  • D.Ethyl indoline-3-acetate

Answer: B

The major product is (B), ethyl indole-3-acetate.

(i) K2CO3 lets the secondary amine displace the allylic bromide, giving the N-benzyl-N-(4-ethoxycarbonylbut-2-enyl) aryl iodide. (ii) Pd(0) adds oxidatively to the C-I bond, and an intramolecular Heck reaction closes a five-membered ring (5-exo); beta-hydride elimination and isomerisation give the aromatic indole with a CH2CO2Et group at C3. (iii) H2 over Pd/C in acetic acid removes the N-benzyl group by hydrogenolysis, giving the free N-H indole.

The quinoline-type products (A) and (C) would need a six-membered (6-endo) cyclisation, which the intramolecular Heck reaction does not favour here. (D), the indoline, would need the aromatic indole C2=C3 bond to be hydrogenated, which these mild conditions do not do.

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