Discussion
Match the following:
| Reaction | Type of reaction | |
|---|---|---|
| (i) | C6H5CHO + Con. NaOH, heat | (a) Oxidation |
| (ii) | C6H5CHO with HNO3/H2SO4, 273-283 K | (b) Reduction |
| (iii) | C6H5COCH3 with NaOX | (c) Disproportionation |
| (iv) | C6H5COCH3 with Zn-Hg/HCl | (d) Electrophilic substitution |
| (e) Addition |
Answer: D
The matching is (i)-(c), (ii)-(d), (iii)-(a), (iv)-(b).
(i) Benzaldehyde with concentrated NaOH is the Cannizzaro reaction: one molecule is oxidised to benzoate and another reduced to benzyl alcohol, a disproportionation (c). (ii) Nitration of benzaldehyde with HNO3/H2SO4 at 273-283 K is electrophilic substitution, giving m-nitrobenzaldehyde (d).
(iii) Acetophenone with sodium hypohalite is the haloform reaction, which oxidises the methyl ketone to benzoate (a). (iv) Zn-Hg and HCl is the Clemmensen reduction of C=O to CH2, giving ethylbenzene (b). Addition (e) fits none of them.
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