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What will be the output of the program ?

#include <stdio.h>

int main()
{
    int a[5] = {5, 1, 15, 20, 25};
    int i, j, m;
    i = ++a[1];
    j = a[1]++;
    m = a[i++];
    printf("%d, %d, %d", i, j, m);
    return 0;
}

 

  • A.2, 1, 15
  • B.1, 2, 5
  • C.3, 2, 15
  • D.2, 3, 20

Answer: C

Correct answer: 3, 2, 15

Take the three statements in order, starting from a = {5, 1, 15, 20, 25}.

  1. i = ++a[1]; - pre-increment: a[1] becomes 2 and that new value is assigned, so i = 2.
  2. j = a[1]++; - post-increment: j = 2 (the old value), and a[1] becomes 3.
  3. m = a[i++]; - the subscript is the old i, so m = a[2] = 15, and i then becomes 3.

The printed values are therefore 3, 2, 15.

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