Discussion
What will be the output of the program ?
#include <stdio.h>
void fun(int **p);
int main()
{
int a[3][4] = {1, 2, 3, 4, 4, 3, 2, 8, 7, 8, 9, 0};
int *ptr;
ptr = &a[0][0];
fun(&ptr);
return 0;
}
void fun(int **p)
{
printf("%d\n", **p);
}
Answer: A
Correct answer: 1
ptr is set to &a[0][0], the address of the first element. fun receives &ptr, so inside it p points at ptr: one dereference gives ptr itself, and the second gives what ptr points to. So **p is a[0][0], which is 1.
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