Discussion
Consider the declaration
char street[10] = "abcdefghi";
Choose the correct remark(s)
Answer: D
Correct answer: None of the above
All three remarks are false.
&streetandstreethold the same address - the start of the array - and differ only in type.&streetis perfectly meaningful: it has typechar (*)[10].- Because of that type,
&street + 1advances 10 bytes whilestreet + 1advances 1, so the two differ.
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