Discussion
Data sequence "1101100001" transmitted at a speed of 1,00,000 bits/sec with a carrier frequency of 150 kHz corresponds to ................. two-bit symbols/sec.
Answer: B
The symbol rate is 50,000 two-bit symbols per second.
Each symbol carries 2 bits, so the symbol (baud) rate is half the bit rate:
\[ \begin{aligned} R_{s} &= \frac{100000\ \text{bits/s}}{2\ \text{bits/symbol}} \\ &= 50000\ \text{symbols/s} \end{aligned} \]
The carrier frequency of 150 kHz and the particular data sequence do not affect the symbol rate; they are distractors. 1,00,000 is the bit rate itself, 25,000 would be for four-bit symbols, and 30,000 does not follow from the data.
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