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The orbital described by the quantum numbers n=4 and \(l\) = 2 is

  • A.4s
  • B.3d
  • C.2d
  • D.4f
  • E.4d

Answer: E

The orbital is 4d.

The principal quantum number gives the shell (4), and \(l = 2\) is a d subshell (\(l = 0, 1, 2, 3\) are s, p, d, f). So the orbital is 4d.

4s has \(l = 0\) and 4f has \(l = 3\). 3d has \(n = 3\). 2d does not exist, because \(l\) must be less than \(n\).

A general rule worth carrying: for a shell \(n\), the allowed \(l\) values run from 0 to \(n - 1\), so the first d subshell is 3d and the first f subshell is 4f.

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