Discussion
The wavelength of a fast moving particle (λ) is related to its momentum (p) and Planck's constant (h) as
Answer: C
The relation is \(\lambda = h/p\), the de Broglie relation.
De Broglie proposed that a moving particle has a wave nature with wavelength inversely proportional to its momentum, \(\lambda = \frac{h}{p} = \frac{h}{mv}\). The faster or heavier the particle, the shorter its wavelength.
A quick unit check rules out the rest: \(h\) is in J s and \(p\) in kg m s\(^{-1}\), so \(h/p\) is in metres, a length. \(hp\), \(h^{2}/p\), \(p^{2}/h\) and \(h/p^{2}\) do not reduce to metres, so none can be a wavelength.
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