Discussion
Which of the following statements are incorrect about boundary surface diagram of orbital?
(i) A boundary surface is drawn in space for an orbital on which the value of probability density| Ψ |2 is constant.
(ii) The boundary surface for | Ψ |2 and | Ψ | are not identical.
(iii) The density of the dots represents the probability density of finding the electron in the region.
(iv) In 1s and 2s orbitals, the probability of finding electron at a given distance is not equal in all the directions.
(v) The 2p orbitals in the boundary surface diagram are not spherical.
Answer: C
The incorrect statements are (ii) and (iv).
(ii) is wrong: |Ψ|2 is constant wherever |Ψ| is constant, so a boundary surface of constant |Ψ|2 is also one of constant |Ψ|; the two surfaces are identical. (iv) is wrong: 1s and 2s orbitals are spherically symmetric, so at a given distance from the nucleus the probability of finding the electron is the same in every direction.
(i) is the definition of a boundary surface, and (v) is true since p orbitals are dumb-bell shaped. (iii) correctly describes the dot (charge cloud) representation, in which the density of dots shows the probability density. So the pair of incorrect statements is (ii) and (iv), and every option including (i) or (iii) is wrong.
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