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According to Hund's rule, most stable state for np2 configuration is ..........

  • A.\(^{1}S_{0}\)
  • B.\(^{3}P_{0}\)
  • C.\(^{3}P_{1}\)
  • D.\(^{3}P_{2}\)

Answer: B

The most stable state is 3P0.

The np2 configuration gives the terms 3P, 1D and 1S. By Hund's first rule the term of highest multiplicity, 3P, lies lowest. It splits into J = 0, 1, 2 (L + S down to |L − S|).

Hund's third rule picks the level: for a subshell less than half full the lowest J lies lowest. Two electrons in a p subshell that can hold six is less than half full, so 3P0 is the ground state, as in carbon. 3P2 would be the ground level of a more than half-filled shell (np4), 3P1 lies between them, and 1S0 is the highest of the three terms.

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