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Averaging three units is better than median voting. Is this correct?

  • A.No, an outlier pulls the average
  • B.Yes, averaging reduces noise
  • C.Yes, provided all three are serviceable
  • D.No, because averaging is harder to compute

Answer: A

Correct answer: No, an outlier pulls the average

Averaging is not better. A faulty unit's output drags the mean in proportion to how far it has strayed, so a single large error corrupts the result - with readings of \( 088.0, 088.3 \) and \( 093.5 \) degrees the mean is about \( 089.9 \), nearly two degrees from where the two healthy units agree.

The median is \( 088.3 \) and is unaffected however far the outlier lies. Averaging also conceals the fault instead of isolating it, so the failed unit continues to contribute. Computational cost is not the issue; both operations are trivial.

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