Discussion
A catalyst converts \( 96 \) per cent of the carbon monoxide entering at \( 12 \) g/km. The tailpipe emission is
Answer: C
Correct answer: 0.48 g/km
A 96 per cent conversion leaves 4 per cent:
\[ 12 \times 0.04 = 0.48\ \mathrm{g/km} \]
The distractor 11.52 is the amount converted rather than the amount remaining. The figure shows how much a catalyst does: without it the vehicle would emit twelve grams a kilometre, an order of magnitude above any modern limit. It also shows why light-off matters - before the catalyst is hot, the full 12 g/km passes through.
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