Discussion
Sulphur in diesel falls from \( 350 \) to \( 10 \) parts per million. The reduction is
Answer: B
Correct answer: 97.1 per cent
The reduction is measured against the original level:
\[ \frac{350 - 10}{350} \times 100 = 97.1\% \]
Removing all but a fortieth of the sulphur was an expensive refinery investment, and it was undertaken because the aftertreatment could not work otherwise. The distractor 2.9 per cent is the fraction remaining, which is a useful check - the two must sum to 100.
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