Discussion
The average of 5 consecutive integers starting with m is n. What is the average of 6 consecutive integers starting with (m+2) ?
Answer: A
The average is \(\frac{2n+5}{2}\).
Five consecutive integers starting at m are m to m + 4, and their average is the middle one: \(n = m + 2\). Six consecutive integers starting at m + 2 run from m + 2 to m + 7, and their average is the midpoint of the ends:
\[ \begin{aligned} \text{average} &= \frac{(m+2) + (m+7)}{2} = m + 4.5 \\ &= n + 2.5 = \frac{2n + 5}{2} \end{aligned} \]
n + 2 and n + 3 are near misses on either side of n + 2.5, and \(\frac{n+5}{2}\) halves n by mistake.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development