Discussion

What is the average of first 95 natural numbers?

Answer: B

The average is 48.

The first \(n\) natural numbers form an arithmetic progression, so their average is the average of the first and last terms:

\[ \text{average} = \frac{1 + 95}{2} = 48 \]

Equivalently, the sum is \(\frac{95 \times 96}{2} = 4560\), and \(4560 \div 95 = 48\).

50 is the average of the first 99 numbers, 49 of the first 97 and 51 of the first 101; each comes from using the wrong last term.

No comment is present. Be the first to comment.

Loading…