Discussion
A virtual link has a bandwidth allocation gap of 4 milliseconds and a maximum frame of 1000 bits. Its maximum rate is
Answer: D
Correct answer: 250 kilobits per second
The bandwidth allocation gap is the minimum interval between successive frames on a virtual link, so the maximum rate is one maximum-size frame per gap:
\[ \frac{1000\ \mathrm{bits}}{4 \times 10^{-3}\ \mathrm{s}} = 250\,000\ \mathrm{bit/s} = 250\ \mathrm{kbit/s} \]
This is the mechanism that makes an Ethernet network deterministic. Every virtual link's traffic is bounded in advance by its own gap and frame size, so the total offered to any switch port can be computed and the worst-case delay demonstrated.
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