Discussion
Arrange these error control mechanisms by increasing strength:
1. A single parity bit
2. A checksum over the message
3. A cyclic redundancy check
4. A cyclic redundancy check with redundant transmission
Select the correct sequence.
Answer: C
Correct answer: 1, 2, 3, 4
The order is one of increasing detection capability. A single parity bit catches any odd number of errors and no even number at all.
A checksum over the message catches more, since it depends on the values as well as their count, but is still fooled by compensating errors. A cyclic redundancy check is far stronger, detecting all burst errors shorter than its own length. Adding redundant transmission is stronger again, since a fault must corrupt two copies identically to pass. Each step costs bits and computation for the detection it buys.
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