Discussion
A friction pendulum bearing of radius 1.0 m has an isolated period of about
Answer: A
Correct answer: 2.0 s
\[ T = 2\pi\sqrt{\frac{R}{g}} = 2\pi\sqrt{\frac{1.0}{9.81}} = 2\pi \times 0.319 = 2.0\ \mathrm{s}. \] The remarkable feature of the friction pendulum is that the mass cancels out entirely, exactly as it does for a simple pendulum: the period depends on the radius of the sliding surface alone, so the isolated period does not change as the building is loaded or altered.
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