Discussion
A modular transmits symbols, each of which has sixty four different possible states, 10,000 times per second. The baud rate and bit rate are :
Answer: A
The rates are 10 kbaud and 60 kb/s.
The baud rate is the number of symbols sent per second: 10,000 symbols per second is 10 kbaud. Each symbol has 64 possible states, so it carries
\[ \begin{aligned} \log_{2} 64 &= 6\ \text{bits per symbol} \\ R_{b} &= 6 \times 10\,000 = 60\ \text{kb/s} \end{aligned} \]
30 kb/s would be 3 bits per symbol (8 states), and 10 kb/s treats each symbol as one bit. The option 0.64 Mbaud wrongly multiplies the number of states by the symbol rate.
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