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A modular transmits symbols, each of which has sixty four different possible states, 10,000 times per second. The baud rate and bit rate are :

  • A.10 kbaud, 60 kb/s
  • B.10 kbaud, 30 kb/s
  • C.0·64 Mbaud, 60 kb/s
  • D.10 kbaud, 10 kb/s

Answer: A

The rates are 10 kbaud and 60 kb/s.

The baud rate is the number of symbols sent per second: 10,000 symbols per second is 10 kbaud. Each symbol has 64 possible states, so it carries

\[ \begin{aligned} \log_{2} 64 &= 6\ \text{bits per symbol} \\ R_{b} &= 6 \times 10\,000 = 60\ \text{kb/s} \end{aligned} \]

30 kb/s would be 3 bits per symbol (8 states), and 10 kb/s treats each symbol as one bit. The option 0.64 Mbaud wrongly multiplies the number of states by the symbol rate.

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