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Plot of the modulus versus temperature of different types of polymers is given below. Based on this plot and the nature of the polymers as mentioned below, find out the correct combination.

Modulus against temperature: a common glassy plateau and drop, after which P falls to zero, Q levels at a low plateau, R holds a higher plateau then falls sharply to zero, and S keeps a high plateau

1 = An amorphous polymer of high molecular weight having entanglements
2 = An amorphous polymer of moderate molecular weight
3 = Highly crosslinked polymer
4 = Semi-crystalline polymer

  • A.P-2; Q-1; R-3; S-4
  • B.P-1; Q-2; R-3; S-4
  • C.P-2; Q-1; R-4; S-3
  • D.P-1; Q-3; R-4; S-2

Answer: C

The match is P-2; Q-1; R-4; S-3.

All four polymers share the glassy plateau and the fall in modulus through the glass transition. What follows tells them apart:

  • P drops straight to zero, flowing as soon as it softens: an amorphous polymer of moderate molecular weight, with too few entanglements for a rubbery plateau.
  • Q levels off at a low rubbery plateau before slowly declining: entanglements in a high molecular weight amorphous polymer act as temporary crosslinks.
  • R holds a higher plateau that ends abruptly: a semi-crystalline polymer, stiffened by its crystallites until they melt.
  • S keeps a high, nearly flat modulus to the highest temperatures: a highly crosslinked polymer, which cannot flow.

Options assigning the crosslinked polymer to R or the semi-crystalline polymer to S get the end of the plateau wrong.

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