Discussion
A thin-walled circular tube of \( 100 \) mm radius and \( 2 \) mm wall has a second moment of area about a diameter of nearest to
Answer: D
Correct answer: 6.28e6 mm^4
For a thin tube, \[ I = \pi r^3 t = \pi \times 100^3 \times 2 = 6.28\times10^6\ \mathrm{mm^4}. \] The cube on the radius is what makes a tube so efficient: doubling the radius at constant wall thickness multiplies the stiffness eightfold for twice the material.
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