Discussion
Four booms of \( 600 \) mm\( ^2 \) each lie \( 150 \) mm above and below the neutral axis. The section's second moment of area is
Answer: B
Correct answer: 5.4e7 mm^4
All four booms are at the same distance, so all four contribute equally: \[ 4 \times 600 \times 150^2 = 2400 \times 22{,}500 = 5.4\times10^7\ \mathrm{mm^4}. \] Whether a boom is above or below the axis makes no difference, since the distance is squared.
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