Machine-translated by Google. Questions are authored in English.
Top

Discussion

For that same section, the larger principal second moment of area is nearest to

  • A.6.00e6 mm^4
  • B.3.17e6 mm^4
  • C.1.20e7 mm^4
  • D.8.83e6 mm^4

Answer: D

Using \( I_{1,2} = (I_{xx}+I_{yy})/2 \pm \sqrt{((I_{xx}-I_{yy})/2)^2 + I_{xy}^2} \), the mean is \( 6 \times 10^6 \) and the radius is \( \sqrt{2^2 + 2^2} = 2.83 \times 10^6 \), giving \( 8.83 \times 10^6 \) mm\( ^4 \). The smaller principal value is \( 3.17 \times 10^6 \).

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.