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Why is a transistor's base made very thin?

  • A.So most injected carriers reach the collector
  • B.So its resistance is as low as the design allows
  • C.So its capacitance to the emitter stays small
  • D.So the breakdown voltage of the device is raised

Answer: A

The base must be thin compared with the diffusion length, so carriers injected from the emitter cross it and reach the collector before recombining - which is what makes the collector current nearly equal to the emitter current and the base current small. A thin base actually raises the base resistance, and capacitance and breakdown voltage are affected in ways that constrain rather than motivate the design. Transistor action is entirely a matter of carriers surviving the base, and every geometric choice serves that.

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