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A transistor has \( \alpha = 0.98 \). Its beta is

  • A.0.98
  • B.50
  • C.49
  • D.98

Answer: C

Converting between the two gains:

\[ \beta = \frac{\alpha}{1-\alpha} = \frac{0.98}{0.02} = 49 \]

so 49. Ninety-eight mistakes alpha's decimals for the answer, and fifty would follow from an alpha of 0.9804. The steepness of this relation is the important part: raising alpha from 0.98 to 0.99 doubles beta to 99, which is why manufacturing spreads in alpha appear as enormous spreads in beta.

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