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A transistor carries \( I_{B} = 20 \ \mathrm{\mu A} \) with \( \beta = 100 \). Its collector and emitter currents are

  • A.2 mA and 2.02 mA
  • B.2 mA and 1.98 mA
  • C.20 mA and 20.2 mA
  • D.0.2 mA and 0.22 mA

Answer: A

Applying beta and then Kirchhoff's current law at the device:

\[ \begin{aligned} I_{C} &= 100 \times 20\mathrm{\mu} = 2 \ \mathrm{mA} \\ I_{E} &= 2 + 0.02 = 2.02 \ \mathrm{mA} \end{aligned} \]

so 2 mA and 2.02 mA. The emitter current is the largest of the three, since it supplies both the others - a check worth making, because an answer with the emitter current smallest has a sign error somewhere.

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