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What is the leakage current between collector and base with the emitter open?

  • A.A current equal to the collector current divided by beta
  • B.A current that falls as the collector voltage rises
  • C.A reverse saturation current that doubles with temperature
  • D.A forward current set by the base-emitter drop

Answer: C

With the emitter out of circuit the collector-base junction is simply a reverse-biased diode, so its leakage is a reverse saturation current, roughly doubling every ten degrees. It is not set by the base-emitter drop, is unrelated to beta, and grows slightly rather than falling with voltage. This leakage is amplified by beta in the common-emitter configuration, which is why thermal stability is such a preoccupation in transistor biasing. Framing the question as which quantity the change acts upon makes the answer follow without calculation.

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