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What penalty does heavy overdrive impose on a switching transistor?

  • A.A higher saturation voltage when conducting
  • B.A greater leakage current in the off state
  • C.A reduced collector-emitter breakdown voltage
  • D.A longer storage time at turn-off

Answer: D

Overdrive fills the base with excess stored charge, and that charge must be removed before the device can begin to turn off, which appears as storage delay. The saturation voltage actually falls slightly with more drive, and neither leakage nor breakdown voltage is affected. The remedy is a Schottky clamp or a speed-up capacitor, both of which prevent the device from saturating deeply - a good example of designing around a limit rather than accepting it.

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