Discussion
What will be the output of the following C code?
#include <stdio.h>
int main()
{
int x = -2;
if (!0 == 1)
printf("yes\n");
else
printf("no\n");
}
Answer: A
Correct answer: yes
The trap is precedence: ! binds tighter than ==, so the expression parses as (!0) == 1, not as !(0 == 1).
The logical NOT of zero is 1 by definition - C's relational and logical operators yield exactly 0 or 1 - so the test becomes 1 == 1, which is true, and yes is printed. Note that x is never used at all; declaring it is a distraction. Even the other reading would have given the same result here, since 0 == 1 is false and !false is true.
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