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A stage has \( V_{CC} = 15 \ \mathrm{V} \), \( R_{C} = 3 \ \mathrm{k\Omega} \) and \( R_{E} = 1 \ \mathrm{k\Omega} \). The saturation current is

  • A.1.25 mA
  • B.3.75 mA
  • C.5 mA
  • D.15 mA

Answer: B

At saturation the whole supply appears across the two resistors:

\[ I_{C(sat)} = \frac{15}{3000+1000} = 3.75 \ \mathrm{mA} \]

giving 3.75 mA. Five milliamps uses the collector resistor alone and forgets the emitter, which is the commonest slip. Including every resistance in the collector-emitter path is what makes the intercept come out, and it is worth listing them explicitly before dividing.

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