Discussion
In a voltage divider bias, what fixes the emitter current?
Answer: C
With the base held at a fixed voltage, the emitter sits one junction drop below it and the emitter resistor then sets the current - a calculation containing no device parameter at all. The third option is the beta-dependent route the arrangement exists to avoid. That the answer can be written without beta appearing anywhere is the whole point, and it is what the stability factor of such a stage reflects. A single measurement chosen to respond to the one asymmetry beats several that respond to shared behaviour.
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