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How does a diode in the bias network compensate for temperature?

  • A.Its drop falls with temperature like the transistor's
  • B.Its leakage current rises to cancel the transistor's own leakage
  • C.Its forward resistance falls and stiffens the divider as things warm
  • D.Its capacitance changes to compensate the shift in operating point

Answer: A

A diode's forward drop falls at the same two millivolts per degree as the transistor's, so placing it in the bias path makes the base voltage track the required drop. Leakage cancellation, resistance changes and capacitance play no part. Compensating a temperature-dependent parameter with an identical device at the same temperature is a technique that recurs throughout analogue design, and it works only because the two really do match. Most errors on this topic come from carrying a result across from a neighbouring scheme where it does not hold.

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